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Question: | 1g Bromine (Br) + 1g Iron (Fe) |
Solution: | Iron(III) bromide (FeBr3) |
Chemical Equation: | 2Fe + 3Br₂ → 2FeBr₃ |
Explanation: | Mixing 1g of bromine (Br₂) with 1g of iron (Fe) leads to a vigorous reaction 💥. Iron readily oxidizes, losing electrons (Fe → Fe³⁺ + 3e⁻), while bromine is reduced, gaining electrons (Br₂ + 2e⁻ → 2Br⁻). This redox reaction forms iron(III) bromide (FeBr₃). The exact yield depends on the reaction conditions and purity of reactants. A PhD-level experiment would involve precise mass measurements, controlled atmosphere (to prevent further oxidation of FeBr3), and characterization techniques (like XRD or X-ray photoelectron spectroscopy 🔬) to confirm product identity and purity. Note that stoichiometry dictates that more Fe is needed for complete Br₂ reaction. The 1g:1g ratio will lead to some unreacted Br₂ remaining. 🧪 |
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