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Question: | 1 Sodium (Na) + 1 Fluorine (F) |
Solution: | Sodium fluoride (NaF) |
Chemical Equation: | Na + F β NaF |
Explanation: | Sodium (Na), an alkali metal π, readily loses one electron to achieve a stable electron configuration. Fluorine (F), a halogen π, readily gains one electron to also achieve a stable configuration. The opposite charges (+1 for NaβΊ and -1 for Fβ») attract, forming an ionic bond π€ to create the ionic compound sodium fluoride (NaF). |
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