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| Question: | 5l Water (H2O) + 1g Sodium (Na) |
| Solution: | A violent reaction producing hydrogen gas and sodium hydroxide. |
| Chemical Equation: | 2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g) |
| Explanation: | Sodium (Na) is a highly reactive alkali metal 💥. When it comes into contact with water, it readily donates its electron to water molecules, causing a rapid oxidation-reduction reaction. This leads to the formation of sodium hydroxide (NaOH), a strong base 🫗, and hydrogen gas (H₂), which is highly flammable 🔥. The reaction is exothermic (releases heat) and can be quite vigorous, even explosive depending on the amount of sodium used. The equation shows that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas. The quantities provided (5L of water and 1g of sodium) need to be converted to moles to determine limiting reactant and extent of the reaction. |
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