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Accepted Answer
| Question: | Oxigeno Carbon (C) + Oxigeno Molybdenum (Mo) |
| Solution: | The reaction between carbon (C) and molybdenum (Mo) in the presence of oxygen is complex and depends on the specific conditions. Here's a simplified explanation: |
| Chemical Equation: | C + Mo + O₂ → MoO₃ + CO₂ |
| Explanation: | At high temperatures, carbon can act as a reducing agent. It reacts with molybdenum oxide (MoO₃) to produce carbon dioxide (CO₂) and molybdenum metal (Mo). 🧪 The reaction can be represented by the following chemical equation: C + MoO₃ → Mo + CO₂. This reaction is often used in the extraction of molybdenum from its ores. ⛏️ However, in the presence of excess oxygen, molybdenum can oxidize further to form molybdenum trioxide (MoO₃). 💨 So, the final product will depend on the relative amounts of carbon, molybdenum, and oxygen present. ⚖️ |
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