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Accepted Answer
Question:

2.5l Hydrogen (H) + 10g Oxygen (O)

Solution: Water (H₂O) and leftover Hydrogen
Chemical Equation: 2H₂ + O₂ → 2H₂O
Explanation: This reaction involves combining hydrogen and oxygen gases to produce water. First, we need to convert the given quantities to moles. 2.5L of H₂ at STP (Standard Temperature and Pressure) is approximately 0.11 moles (using the ideal gas law PV=nRT, where R=0.0821 Latm/molK). 10g of O₂ is approximately 0.31 moles (molar mass of O₂ is 32 g/mol). 🤔The balanced equation shows a 2:1 molar ratio of H₂ to O₂. We have less H₂ than needed to react with all the O₂, so H₂ is the limiting reactant. 🧪The 0.11 moles of H₂ will react with 0.055 moles of O₂ to produce 0.11 moles of H₂O. 🎉Excess O₂ (0.31-0.055=0.255 moles) will remain.💧

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